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Determine length of an audio sample in seconds by Perturbatio
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Author:
Archive
| Viewed:
590
times | Language:
BlitzMax
| Category:
Sound
SuperStrict Local sample:TAudioSample = LoadAudioSample("battle.ogg") Local length:Float = getSampleLength(sample) Print "Length in seconds: " + length Print "Length: " + Int(Floor(length/60))+"m "+Int(length Mod 60)+"s" Function getSampleLength:Float(sample:TAudioSample) Return Float( (sample.length / Float( (sample.hertz * 60) ) ) * 60) End Function
Author Comments:
Determine length of an audio sample in seconds (tested with OGG files, but it should be the same for any file)
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